Cos(8x)=2cos^2(4x)-1

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Solution for Cos(8x)=2cos^2(4x)-1 equation:


Simplifying
Cos(8x) = 2cos2(4x) + -1

Remove parenthesis around (8x)
osC * 8x = 2cos2(4x) + -1

Reorder the terms for easier multiplication:
8osC * x = 2cos2(4x) + -1

Multiply osC * x
8osxC = 2cos2(4x) + -1

Remove parenthesis around (4x)
8osxC = 2cos2 * 4x + -1

Reorder the terms for easier multiplication:
8osxC = 2 * 4cos2 * x + -1

Multiply 2 * 4
8osxC = 8cos2 * x + -1

Multiply cos2 * x
8osxC = 8cos2x + -1

Reorder the terms:
8osxC = -1 + 8cos2x

Solving
8osxC = -1 + 8cos2x

Solving for variable 'o'.

Move all terms containing o to the left, all other terms to the right.

Add '-8cos2x' to each side of the equation.
-8cos2x + 8osxC = -1 + 8cos2x + -8cos2x

Combine like terms: 8cos2x + -8cos2x = 0
-8cos2x + 8osxC = -1 + 0
-8cos2x + 8osxC = -1

Reorder the terms:
1 + -8cos2x + 8osxC = -1 + 1

Combine like terms: -1 + 1 = 0
1 + -8cos2x + 8osxC = 0

The solution to this equation could not be determined.

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